By: Prem Tiwari | Last Updated: | In: C++ Tutorial
We assume you have basic knowledge of c++ programming language. In this program, we have used the if…else statement to check even or odd, entered by the user during program execution.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | #include <iostream> using namespace std; int main() { int n; cout << "Enter an integer: "; cin >> n; if ( n % 2 == 0) cout << n << " is even."; else cout << n << " is odd."; return 0; } |
#first try
Enter an integer: 12
12 is even.
#second try
Enter an integer: 51
51 is odd.
Prem Tiwari is the founder of FreeWebMentor.com and also a professional developer who has vast experience in PHP and open source technologies. Apart from this, he is a blogger by hobby and also he has been a regular speaker of WordPress sessions in various IT Companies. View all posts by Prem Tiwari
Tags: c program, c programs, c++ program to check odd and even numbers, C++ Tutorial, odd and even number programs
