Editorial Staff - - C++ Tutorial
In this program, we are going to share a C++ Program to Implement Gauss-Seidel Method with the output. If you are a beginner and want to start learning the C++ programming, then keep your close attention in this tutorial as I am going to share a program for C++ Program to Implement Gauss-Seidel Method.
Copy the below C++ program and execute it with the help of GCC compiler. At the end of this program, We have shared the output of this program.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 | #include #include using namespace std; int main(void) { float a[10][10], b[10], x[10], y[10]; int n = 0, m = 0, i = 0, j = 0; cout << "Enter size of 2d array(Square matrix) : "; cin >> n; for (i = 0; i < n; i++) { for (j = 0; j < n; j++) { cout << "Enter values no :(" << i << ", " << j << ") "; cin >> a[i][j]; } } cout << "\nEnter Values to the right side of equation\n"; for (i = 0; i < n; i++) { cout << "Enter values no :(" << i << ", " << j << ") "; cin >> b[i]; } cout << "Enter initial values of x\n"; for (i = 0; i < n; i++) { cout << "Enter values no. :(" << i<<"):"; cin >> x[i]; } cout << "\nEnter the no. of iteration : "; cin >> m; while (m > 0) { for (i = 0; i < n; i++) { y[i] = (b[i] / a[i][i]); for (j = 0; j < n; j++) { if (j == i) continue; y[i] = y[i] - ((a[i][j] / a[i][i]) * x[j]); x[i] = y[i]; } printf("x%d = %f ", i + 1, y[i]); } cout << "\n"; m--; } return 0; } |
Enter size of 2d array(Square matrix) : 3
Enter values no :(0, 0) 2
Enter values no :(0, 1) 3
Enter values no :(0, 2) 1
Enter values no :(1, 0) 5
Enter values no :(1, 1) 4
Enter values no :(1, 2) 6
Enter values no :(2, 0) 8
Enter values no :(2, 1) 7
Enter values no :(2, 2) 9
Enter Values to the right side of equation
Enter values no :(0, 3) 2
Enter values no :(1, 3) 3
Enter values no :(2, 3) 4
Enter initial values of x
Enter values no. :(0): 0
Enter values no. :(1): 0
Enter values no. :(2): 0
Enter the no. of iteration : 4
x1 = 1.000000 x2 = -0.500000 x3 = -0.055556
x1 = 1.777778 x2 = -1.388889 x3 = -0.055556
x1 = 3.111111 x2 = -3.055555 x3 = 0.055555
x1 = 5.555555 x2 = -6.277777 x3 = 0.388889
