What is the best way to validate an XML file against an XSD file?
The Java runtime library supports validation. Last time I checked this was the Apache Xerces parser under the covers. You should probably use a javax.xml.validation.Validator.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.*; import java.net.URL; import org.xml.sax.SAXException; //import java.io.File; // if you use File import java.io.IOException; ... URL schemaFile = new URL("http://host:port/filename.xsd"); // webapp example xsd: // URL schemaFile = new URL("https://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"); // local file example: // File schemaFile = new File("/location/to/localfile.xsd"); // etc. Source xmlFile = new StreamSource(new File("web.xml")); SchemaFactory schemaFactory = SchemaFactory .newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); try { Schema schema = schemaFactory.newSchema(schemaFile); Validator validator = schema.newValidator(); validator.validate(xmlFile); System.out.println(xmlFile.getSystemId() + " is valid"); } catch (SAXException e) { System.out.println(xmlFile.getSystemId() + " is NOT valid reason:" + e); } catch (IOException e) {} |
You should not use the DOMParser to validate a document (unless your goal is to create a document object model anyway). This will start creating DOM objects as it parses the document – wasteful if you aren’t going to use them.
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